At the city museum, child admission is 6.30 and adult admission is 9.50. On Saturday, three times as many adult tickets as child tickets were sold for total sales of $1113.60 . How many child tickets were sold that day?

There were 29 child's tickets sold that day.

Step-by-step explanation:

The first we need to do is assign variables to what our "unknowns" are. Let's say the number of adult tickets will be "A" and the number of child's tickets will be "C". We will use two equations to solve this problem

First, we know that each adult ticket is $8.90 and each child ticket is $5.30. When we add up the sales total for both types of tickets, the total sale is $928. We can represent this with the following equation:

$8.90A + $5.30C = $928

Next, we know that if we multiply the number of child's tickets by 3, we will get the number of adult tickets:

3 * C = A                                                                                                              Now, we can substitute 3 * C in for "A" in our first equation and solve:        8.9 (3C) + 5.3C = 928

26.7C + 5.3C = 928

32C = 928

C = 29

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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