AD = 6, DC = 8, find DB

10

Step-by-step explanation:

use a^2+b^2=c^2

6^2+8^2=c^2

100=c^2

sqrt it and you get 10 for AC and AC=DB

according to Pythagoras theorem, c²=a²+b²

|AC|²=|AD|²+|DC|²

|AC|²=6²+8²

|AC|²=36+64

|AC|²=100

√|AC|²=√100

|AC|=10

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)