PLS HELP ASAP (Sorry its glitched)
Answer two questions about Systems and :
System \text{\quad}start text, end text System
{8x−3y=02x+7y=3\begin{cases}8x-3y=0 2x+7y=3\end{cases}⎩⎪⎪⎨⎪⎪⎧​8x−3y=02x +7y=3​ {8x−3y=08x+28y=12\begin{cases}8x-3y =08x+28y=12\end{cases}⎩⎪⎪⎨⎪⎪⎧​8x−3y =08x+28y=12​
1) How can we get System from System ?
Choose 1
Choose 1

(Choice A)
A
Replace one equation with a multiple of itself
(Choice B)
B
Replace one equation with a multiple of the other equation
(Choice C)
C
Replace one equation with itself where the same quantity is added to both sides
(Choice D)
D
Replace one equation with itself where a quantity is added to only one side

2) Based on the previous answer, are the systems equivalent? In other words, do they have the same solution?
Choose 1
Choose 1

(Choice A)
A
Yes
(Choice B)
B
No

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.

the answer is y = 11.54

hope this : )