In a class test (+ 5) marks are given for every correct answer and (-3) marks are given for every incorrect answer. a) Anu gets 8 correct answer and 12 incorrect answers what is her score?
b) Sam answered all the questions and scored 28 marks though he got 11 correct answers.

How many incorrect answers had he attempted?

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a. 4 marks b. 9 questions

Step-by-step explanation:

a) Anu gets 8 correct answer and 12 incorrect answers what is her score?

Since Anu got 8 correct answer and 12 incorrect answers, and + 5 marks is given for every correct answer and (-3) marks are given for every incorrect answer, the total score for correct answers is number of correct answer × marks for correct answer = 8 × (+ 5) = 40.

Also,  the total score for incorrect answers is number of incorrect answer × marks for incorrect answer = 12 × (- 3) = -36.

Anu's total score = total score for correct answers + total score for incorrect answers = 40 + (-36) = 40 - 36 = 4 marks.

So, Anu scored 4 marks.

b) Sam answered all the questions and scored 28 marks though he got 11 correct answers.  How many incorrect answers had he attempted?

Let x be the number of incorrect answers. Since the marks for incorrect answers is -3, then his total score for incorrect answers is -3x.

Since Sam got 11 correct answers and is given + 5 marks for each correct answer, then his total score for correct answers is 11 × (+5) = +55.

Since he gets a total of 28 marks, we have that total score for incorrect answer + total score for correct answer = 28.

So, -3x + 55 = 28

Solving for x, we have

-3x = 28 - 55

-3x = -27

x = -27/-3

x = 9

Since x = 9, Sam attempted 9 incorrect questions.

.

He or she attempted 9 incorrect answers

Step-by-step explanation:

answer: 323 is how many she has ☃☃⛄❄

step-by-step explanation:

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~