The sum of three numbers is 103. The second number is 5 less than the first. The third number is 4 times the first. What are the numbers?

The numbers are 18, 13, and 72.

Step-by-step explanation:

Let the three numbers be represented by a, b, and c.

The sum of the three is 103. Thus, we can write that:

The second number is five less than the first. So:

And the third number is four times the first. So:

Substitute:

Solve for a. Combine like terms:

Add five to both sides:

And divide both sides by six. Therefore:

So, the first number is 18.

Since the second number is five less than the first, the second number is 13.

And since the third number is four times the first, the third number is 72.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

i can't see the picture : /