Solve the following percent puzzle, entering each square of the completed puzzle in the corresponding box below. [asy]
void shademe(pair A) {
fill(A--(A+(1,0))--(A+(1,1))--(A+(0 ,1))--cycle, gray(0.8));
}
size(125);
shademe((2,0));
shademe((1,1));
shademe((0,2));
for(int i=0;i<=3;i+=1){
draw((i,0)--(i,3));
draw((0,i)--(3,i));
}
label("$33\frac13\%$",(0,2.5),W); label("$50\%$",(0,1.5),W);
label("$50\%$", (0,0.5), W);
label("$75\%$", (0.5,3),N);
label("$66\frac23\%$", (1.5,3),N);
label("$11\frac19\%$", (2.5,3), N);
[/asy]

Which ordered pair is a solution of the equation? y + 5 = 2(2+1) choose 1 answer ® only (5,10 ® only (-1,-5) © both (5, 10) and (-1,-5) 0 neither

Finally, the arena decides to offer advertising space on the jerseys of the arena’s own amateur volley ball team. the arena wants the probability of being shortlisted to be 0.14. what is this as a percentage and a fraction? what is the probability of not being shortlisted? give your answer as a decimal. those shortlisted are entered into a final game of chance. there are six balls in a bag (2 blue balls, 2 green balls and 2 golden balls). to win, a company needs to take out two golden balls. the first ball is not replaced. what is the probability of any company winning advertising space on their volley ball team jerseys?

Weekly wages at a certain factory are normally distributed with a mean of $400 and a standard deviation of $50. find the probability that a worker selected at random makes between $450 and $500