In the similarity transformation of ACB to EFD, ACB was dilated by a scale factor of 2 reflected across the y-axis and moved through the translation [?]

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )

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step-by-step explanation:

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