40 points if helped question is in the picture

first term = 15

second term = 9

Third term = 3

Step-by-step explanation:

Let the first term be 3x

Let the second term be = 3x - 6       [ 6 less than first term]

Let the third term be = 1/5 of 3x

Difference between first and third term = 12

That is ,

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

my guess would be b and d, but i didn’t actually get out the pen and paper. lol