Find the probability that when a couple has ​children, at least one of them is a . ​(Assume that boys and girls are equally​ likely.)

Step-by-step explanation:

Given

--- equal probability

See comment for complete question

Required:

To do this, we make use of complement rule:

The event that there is no girl out of the 3 children is: B B B

And the probability is:

So:

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

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step-by-step explanation: