Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 5? Select one:
a. 420
4
20

b. 320
3
20

c. 520
5
20

d. 120
1
20

4 / 20 = 1/5

Step-by-step explanation:

Given that:

Ticket numbering is from 1 - 20

Hence, total possible number of tickets : (1, 2, 3, 4, 5, 6, 7, 8,9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20)

Total possible outcomes = 20

Required outcome = multiples of 5 ; the multiples of 5 from the entire ticket numbers are : 5, 10, 15, 20

Required outcome = 4

P(multiple of 5) = Required outcome / Total possible outcomes

P(multiple of 5) = 4 / 20 = 1 / 5

215.92 dollars is the answer

irrational, then, just means all the numbers that aren't rational. every integer is a rational number, since each integer n can be written in the form n/1. however, numbers like 1/2, 45454737/2424242, and -3/7 are also rational, since they are fractions whose numerator and denominator are integers.

step-by-step explanation: