Express the trigonometric ratios sinA in term of cosA​

To express the trigometric ration sinA in term of cosA

By using property of trignometry

\begin{gathered}sin^{2}{A}+cos^{2}{A}=1 < /p > < p > \\then \\ < /p > < p > sin{A}=\sqrt{1-cos^{2}{A} }\end{gathered}

sin

2

A+cos

2

A=1</p><p>

then

</p><p>sinA=

1−cos

2

A

there u go

its very big question plz make it small