Suppose that the scores on a statewide standardized test are normally distributed with a mean of 64 and a standard deviation of 2. Estimate the percentage of scores that were (a) between 60 and 68.

95. 45%

Step-by-step explanation:

Given :

Mean score, = 64

Standard deviation = 2

Score between 60 and 68

P(Z < (x - mean) / standard deviation)

P(Z < (60 - 64) / 2) = P(Z < - 2) = 0.02275 (Z probability calculator)

P(Z < (68 - 64) / 2) = P(Z < 2) = 0.97725 (Z probability calculator)

P( score between 60 and 68)

P(Z < 2) - P(Z < - 2)

0.97725 - 0.02275 = 0.9545

Score between 60 and 68 = 0.9545 = 0.9545 * 100% = 95.45%

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3