Dose 4(x+1)= 3x+4 have a solution

x = 0

Step-by-step explanation:

First, multiply 4 by x+1

4x + 4 = 3x + 4

Subtract 3x on both sides

x + 4 = 4

Subtract 4 from both sides

x =

this is x = 0, since x = nothing.

x=0

Step-by-step explanation:

4(x+1)= 3x+4

Distribute

4x+4 = 3x+4

Subtract 3x from each side

4x-3x+4 =3x-3x+4

x+4 = 4

Subtract 4 from each side

x+4-4 = 4-4

x=0

sec ф = 5/3 (quadrant 4)

let x = base

y = perp

z = hypotenuse

sec ф = hypotenuse/base = 5/3

⇒ z = 5 and x = 3

finding y:

z² = x² + y²

5² = 3² + y²

y² = 25-9

y² = 16

y = 4

now finding all other geometric functions of theta:

sin ф = y/z = 4/5

sin ф = -4/5 (sin is negative in the 4th quadrant)

cos ф = x/z = 3/5

cos ф = 3/5 (cos is positive in 4th quadrant)

tan ф = y/x = 4/3

tan ф = -4/3 (tan is negative in 4th quadrant)

cosec ф = z/y = 5/4

cosec ф = -5/4 (cosec is negative in the 4th quadrant)

cot ф = x/y = 3/4

tan ф = -3/4 (tan is negative in 4th quadrant)