What calculation will give us the estimated volume of fuel that remains in Carson's tank by the end of the drive, in liters?

The complete question can be found online.

The missing information is:

Carson drove a total distance of 120km, he initially has 30L of fuel on his tank, and his car efficiency is 100 cm^3/km

Remember that 1000cm^3 = 1 L

then:

100cm^3 = 0.1L

This means that he uses 0.1 L per kilometer.

The equation that shows how many liters of fuel he will have is:

initial fuel - consumed fuel.

We know that the initial fuel is 30 liters.

And the consumed fuel will be the amount of fuel he used to drive the 120 km

Remember that for each km, he consumes 0.1 L of fuel.

Then for the 120km he used 120 times 0.1 L of fuel, so he used a total of:

120*0.1 = 12 L of fuel

Then the remaining fuel in the tank is:

30 L - 12 L = 18L

There are 18 L of fuel in the tank.

nope

step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0