Can someone please help me??

The maximum value of the function = 11, at x = 3 and y = 5

The minimum value of the function = -21, at x = 3 and y = -3

Step-by-step explanation:

Given;

F = 4y - 3x

The function is subject to  y ≤ 2x - 1,

                                            y ≥ -2x + 3,

                                               x ≤ 3

           y ≤ 2x - 1  

      -  ( y ≥ -2x + 3)

          0 ≤ 4x - 4

           4 ≤ 4x

            1 ≤ x

thus,   1 ≤  x ≤ 3

When x = 3

y ≤ 2x - 1     ⇒     y ≤ 2(3) - 1,        ⇒ y ≤ 5

y ≥ -2x + 3,  ⇒    y ≥ -2(3) + 3,      ⇒ y ≥ - 3

thus, -3 ≤  y  ≤ 5

When x = 1

y ≤ 2x - 1     ⇒     y ≤ 2(1) - 1,        ⇒ y ≤ 1

y ≥ -2x + 3,  ⇒    y ≥ -2(1) + 3,      ⇒ y ≥ 1

when x = 1 and y = 1

F = 4(1) - 3(1)

F = 1

when y = -3, and x = 3

F = 4(-3) - 3(3)

F = -12 - 9

F = - 21

When y = 5 and x = 3

F = 4(5) - 3(3)

F = 20 - 9

F = 11

Therefore, the maximum value of the function = 11, at x = 3 and y = 5

The minimum value of the function = -21, at x = 3 and y = -3

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

nlgqer

step-by-step