C. P 0f 16 oranges is equal to the Sip of 22
oranges. find profit
percent
or LOSS

Step-by-step explanation:

LCM of 16 and 22 is 176.

Let the CP of 16 oranges be Rs. 176 and also let the SP of 22 oranges be Rs. 176.

So,

➝ CP of 16 oranges = Rs. 176

➝ CP of 1 orange = Rs. 176 ÷ 16

➝ CP of 1 orange = Rs. 11

And,

➝ SP of 22 oranges = Rs. 176

➝ SP of 1 orange = Rs. 176 ÷ 22

➝ SP of 1 orange = Rs. 8

Here, CP is greater than SP. So, here is loss.

➝ Loss = CP ― SP

➝ Loss = Rs.(11 ― 8)

➝ Loss = Rs. 3

Finding the loss%,

★ Loss % = {(Loss/CP) × 100} %

➝ Loss % = {3/11 × 100} %

➝ Loss % = 27.27 %

Therefore, loss% is 27.27%.

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right