A point P(3, k) is first transformed by E¹[0, 2] and then by E²[0,3/2] so that the final image is (9, 12), find the value of k.​​

Hello,

The first transform E1 is the homothetie of center (0,0) and ratio=2

The second transform E2 is the homothetie of center (0,0) and ratio=3/2

P=(3,k)

P'=E1(P)= E1((3,k))=(2*3,2*k)=(6,2k)

P''=E2(P')=E2(6,2k)=(3/2*6,3/2*2*k)=(9,3k)=(9,12)

==> 3k=12

k=4

-18

step-by-step explanation:

because mean value defines that total sum value over total number of set

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10