Write the quadratic form in the form specified then give the vertex of its graph.

Equation: f(x) = 2(x + 5)^2 + 2

Vertex: (-5, 2)

Step-by-step explanation:

The form the question wants us to write the quadratic function in is called "vertex form":

f(x) = a (x - h)^2 + k

a = the a in a standard quadratic equation (y = ax^2 + bx + c) or the coefficient of the x^2

h = x coordinate of the vertex

k = y coordinate of the vertex

To find the vertex, we are going to use the quadratic equation given:

2x^2 + 20x + 52

Comparing it to the standard quadratic equation (y = ax^2 + bx + c),

a = 2

b = 20

c = 52

Now we can start finding our vertex.

To find h, we are going to use this formula:

-b / 2a

We already know b = 20 & a = 2, so we can just substitute that into our formula:

- (20) / 2*2

Which equals:

-20/4 = -5

So h (or the x coordinate of the vertex) is equal to -5

Next we will find k, or the y coordinate of the vertex.

To do that, we are going to plug in -5 into 2x^2 + 20x + 52:

2(-5)^2 + 20(-5) + 52

2(25) -100 + 52

50 - 100 + 52

-50 + 52

2

k (or the y coordinate of the vertex) is equal to 2

The vertex is (-5, 2)

However, we still need to find our equation in vertex form.

We know a = 2, h = -5, & k = 2. Now we substitute these into our vertex form equation:

a(x - h)^2 + k

(2)(x - (-5))^2 + (2)

2(x + 5)^2 + 2

(Remember that the -5 cancels with the - in front of it, making it a positive 5)

The equation is f(x) = 2(x + 5)^2 + 2

Hope it helps (●'◡'●)