If p(A) = 0.2, p(B) = 0.6 and p(AB) = 0.3. Find the following chances: (a) p(B’)
(b) p(A’ B)
(c) p(AB’)
(d) p(A’U B)
(e) p[(A’U B’)]
(f ) p(AUB’)

i think the answer would be c

the awnser is visionary

vertical asymptote .

horizontal asymptote .

step-by-step explanation:

given function is .

vertical asymptote is given by setting

denominator =0

when degree of numerator and denominator are same then divide first term of numerator by first term of denominator to get horizontal asymptote.