find the value of "a" and "b" for which the limit exists both as x approaches 1 and as x approaches 2:

a = 4

b = -2

Step-by-step explanation:

If the given function is continuous at x = 1

And for the continuity of the function at x = 1,

Therefore, (a + b) = 2 -------(1)

If the function 'f' is continuous at x = 2,

Therefore,

2a + b = 6 -----(2)

Subtract equation (1) from (2),

(2a + b) - (a + b) = 6 - 2

a = 4

From equation (1),

4 + b = 2

b = -2

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