use the discriminant to determine the number of solutions to the quadratic equation −6z2−10z−3=0. What are the real solutions and complex solutions?

Step-by-step explanation:

-6z²-10z-3=0

multiply by -1

6z²+10z+3=0

disc .=b²-4ac=10²-4×6×3=100-72=28≥0

also it is not a perfect square.

so roots are real,irrational and different.

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

answer: it's a

step-by-step explanation: