A cylindrical jug that carries 2ℓ of water when it is filled to the brim has a base surface with a diameter of 8cm. What is the length of the jug in cm, rounded to two decimal places?

39.79 cm

Step-by-step explanation:

a few things to make sure :

1 liter = 1 dm³ (a cube of 10cm length of edges) =

= 10×10×10 = 1000 cm³

the volume of a cylinder is

base area × height (or length, as it is called in this question).

and the base area is a circle

area = pi×r²

and r (radius) is half of the diameter.

so, we know r = diameter/2 = 4cm

and the volume is 2 liter = 2 dm³ = 2000 cm³

so, we have

2000 = pi×r² × length = pi×4² × length = pi×16 × length

length = 2000 / (pi × 16) cm = 125 / pi cm =

= 39.79 cm

c. (0.6,-1.4)

step-by-step explanation:

hope this

idk

step-by-step explanation: