Negating conditional statement (a V ~ b) => c Please show your work and give a proper answer

"p implies q" is equivalent to "(p and q) or not p", which in turn is equivalent to "(p or not p) and (q or not p)". But "p or not p" is always true, so the implication reduces completely to "not p or q". Negating an implication thus gives "not (not p or q)", which is equivalent to "p and not q".

So

not [(a or not b) implies c]   <==>  (a or not b) and not c

x = 25/2304

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i don't have the answer rn but go to math papa. it shows the steps and the answer. hope this : )

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