Given f(x)= 2^x and g(x)=x^2 answer the questions that follow a. Your friend claims the graph of f(x)=2x increases at a faster rate than the graph of g(x)=x2 when x ≥ 0. Is your friend correct? Explain your reasoning.
b. How are the 2 functions different?

PLEASE HELP

a. Yes it's correct, reasons;

I) let x=1, f(1)=2^1=2, g(x)=1^2=1 this proves that when a higher number is used the value of f(x) will be higher than g(x).

ii) As x approaches zero f(x) approaches 1, but g(x) approaches 0. Which will make the rate at which the graph of f(x) increase be faster than g(x)

b. f(x) has an infinite degree but g(x) has a finite degree of 2.

-14 is the answer

hope this : ))

damm bro the struggle

step-by-step explanation: