Find the value of the variable y, where the sum of the fraction 2/y-3 and 6/y+3 is equal to the quotient. PLEASE HEL NEED ASA WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWE

Here we need to solve:

The sum of the fractions is equal to the quotient between the fractions.

Notice that the two values:

y = 3

y = -3

make the denominator equal to zero, so those values are restricted.

We can simplify the right side to get:

Now we can multiply both sides by (y - 3)

Now we can multiply both sides by (y + 3)

First, let's see the determinant of that quadratic equation:

We can see that it is negative, thus, there are no real solutions of the equation.

Thus, there is no value of y such that the origina equation is true,

1e+27

step-by-step explanation: