In the diagram, the ratios of two pairs of corresponding sides are equal. Triangles L M N and X Y Z are shown. Side L M is blank, side M N is 3, and side N L is 2. Side X Y is blank, side Y Z is 9, and side Z X is 6.

To prove that △LMN ~ △XYZ by the SAS similarity theorem, it also needs to be shown that

∠N ≅ ∠Z
∠N ≅ ∠X
∠L ≅ ∠Z
∠L ≅ ∠Y

∠N ≅ ∠Z

Step-by-step explanation:

In the Side-Angle-Side (SAS) similarity theorem, the included angle of the two given sides of a triangle is also given. This theorem relates two legs of a triangle with the angle formed by the legs.

Comparing the sides of △LMN and △XYZ, it would be observed that the corresponding sides of △XYZ has a scale of 3. So to prove that △LMN ~ △XYZ by the SAS similarity theorem, it would be required to also show that ∠N ≅ ∠Z.

the sum of all the angles in a triangle are equal to 180

so you can add   the 3 given angles together to equal 180:

5y + 2y + 2y = 180

or since all three angles have the same letter, combine the 3 angles to equal 180:

9y = 180

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!