Consider A Triangle ABC. Suppose That A= 119 Degrees, B=53, And C=57. Solve The Traingle

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  a = 94.8, B = 29.3°, C = 31.7°

Step-by-step explanation:

Side 'a' can be found using the Law of Cosines:

  a² = b² +c² -2bc·cos(A)

  a = √(2809 +3249 -6042·cos(119°)) ≈ √8987.22 ≈ 94.8

Then one of the other angles can be found from the Law of Sines.

  sin(C)/c = sin(A)/a

  C = arcsin(c/a·sin(A)) ≈ arcsin(0.525874) ≈ 31.7°

Then the remaining angle can be found to be ...

  B = 180° -A -C = 180° -119° -31.7° = 29.3°

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The solution is a ≈ 94.8, B ≈ 29.3°, C ≈ 31.7°.

step-by-step explanation: i dont

50-60=10

step-by-step explanation: