A normal population has mean and standard deviation . (a) What proportion of the population is greater than ? (b) What is the probability that a randomly chosen value will be less than .

0.0171

0.89158

Step-by-step explanation:

Given :

μ = 60

Standard deviation , σ = 17

The probability that a randomly chosen score is greater than 96;

P(Z > Zscore)

Zscore = (score, x - μ) / σ

Zscore = (96 - 60) / 17 = 2.118

P(Z > 2.118) = 1 - P(Z < 2.118) = 1 - 0.9829 = 0.0171

The probability that a randomly chosen score is less than 81;

P(Z < Zscore)

Zscore = (score, x - μ) / σ

Zscore = (81 - 60) / 17 = 1.235

P(Z < 1.235) = 0.89158

7. 153.86 ft

8. 12.56 ft

9. 78.5 m

10. 379.94 in

11. 132.665 m

12. 12.56 yd

13. 226.865 ft

14. 113.04 ft

15. 63.585 ft

16. 254.34 m

17. 50.24 cm

step-by-step explanation:

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answer: finding the extract measurements and knowing the points

step-by-step explanation: