Describe the motion of a particle with position (x, y) as t varies in the given interval. x=3sint, y=1+cost, 0≤t≤3π/2

The motion is centered about (0,1)

Step-by-step explanation:

x = 3sint (1)

y = 1 + cos(t) (2)

x^2 = 9 *sin(t)*sin(t)  

hence; (x^2)/9 = sin(t)*sin(t) (3)

y-1 = cos(t)  

hence; (y-1)^2 = cos(t) * cos(t)   (4)

adding  equation 3 and 4

(x^2)/9 + ( y - 1 )^2 = 1

The motion is centered about (0,1)

y=mx+b is the final answer!   : )

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8