Find the equation of the straight line which is perpendicular to the line 4x - 3y + 2 = 0 and passes through (-2, 3).
RO
CC
-3 X + 4 Y- 6 = 2
Q
O x - 4y - 6 = 0
O
3 X + 4 Y- 6 = 0,
O X+Y-6=5

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

the correct answer is 828.07