PLZ HELP ILL GIVE BRAINLIEST AND CASh A figure is located at (2, 0), (2, −2), (6, −2), and (6, 0) on a coordinate plane. What kind of 3-D shape would be created if the figure was rotated around the x-axis? Provide an explanation and proof of your answer to receive full credit. Include the dimensions of the 3-D shape in your explanation. (10 points)

The 2D shape is a rectangle, because there are two sets of both x and y values. Then, if you were to look at it from the z axis (above), it would look like a line. Because this rectangle doesn't touch the x axis, if you rotated it around, you would make a torus instead of a cylinder. This torus would have a diameter of 12 units - because the farthest point on the x axis is 6 away from 0 - and a height of 2 units - because we aren't rotating it by the y axis. The hole would have a diameter of 4 units because the closest point on the x axis to 0 is 2.

answer;

the correct answer

just use google you beautiful person.

have a nice day < 3

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

~