Help me to solve this fast ( prove it)

Step-by-step explanation:

sec⁴A + tan⁴A = 1 + (2tan²A/cos²A)

LHS = sec⁴A + tan⁴A

= (sec²A)² + (tan²A)² {using formula of a²+b²)

= (sec²A-tan²A) + 2tan²A.sec²A

= 1 + {2tan²A.(1/cos²A)}

= 1 + (2tan²A/cos²A)

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: