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As the opposite angles of a cyclic quadrilateral, A is supplementary with C and B is supplementary with D.

In the trapezoid,  angle A is supplementary with D and angle B is  supplementary with C.

It means ∠A ≅ ∠B and ∠D ≅ ∠C

Now, ∠ABD ≅ ∠ACD as both angles intercept same arc AD.

So we have:

So angles B and A are 107° and angles D and C are 73°

PXR is exterior angle of triangle XSR.

Angles Q and S are supplementary as opposite angles of a cyclic quadrilateral QPSR.

step-by-step explanation: