Jeannine needs to decide what size to make a rectangular garden in her yard. The dimensions must be natural numbers.
Jeannine wants the perimeter of her Chapter Reference
garden to be 50 dm. She wants the
width to be an even number of decimeters. How many
different combinations are possible? (Length is always longer than or equal to width.)

Total number of possible combinations are 6

Length   width

23 dm     2m

21 dm       4 dm

19 dm       6 dm

17 dm         8 dm

15 dm         10 dm

13 dm          12 dm

Step-by-step explanation:

We are given that

Perimeter of rectangular garden=50 dm

Width is  even number.

Length is always longer than or equal to width.

Let length of rectangular garden=x

Width of  rectangular garden=y

We have to find the possible  number of combinations .

Perimeter of rectangular garden=

If y=2 dm

x=25-2=23 dm

If y=4 dm

x=25-4=21 dm

If y=6 dm

x=25-6=19 dm

If y=8 dm

x=25-8=17 dm

If y=10 dm

x=25-10=15 dm

If y=12 dm

x=25-12=13 dm

If y=14 dm

x=25-14=11 dm

x<y

It is  not possible

Then, possible combinations are 6

Length   width

23 dm     2m

21 dm       4 dm

19 dm       6 dm

17 dm         8 dm

15 dm         10 dm

13 dm          12 dm

853.3

step-by-step explanation:

the answer is "add 2y and y"

step-by-step explanation:

you need to collect the like terms first.