Solve by completing the square method 3x²=15-4x ​

Step-by-step explanation:

3x²=15-4x

divide by 3 on both sides

x²=5-x ​ ​

move everything to one side

x²+x ​-5 = 0

add the square of 1/2 the middle term of  but also subtract it too

x²+x +​-5-​ = 0

now use the property of a perfect square to rewrite

-5 - = 0

rewrite 5 as a fraction

- - = 0

add up the fractions

- = 0

move to the other side

=

take the square root of both sides :P

 =

much easier looking now, just use algebra to solve for x

x + =

subtract    from both sides

x + -   = -

x =

:)  

​

x = - 3, x =

Step-by-step explanation:

Given

3x² =15 - 4x ( add 4x to both sides )

3x² + 4x = 15 ← factor out 3 from each term on the left side

3(x² + x) = 15

To complete the square

add/subtract ( half the coefficient of the x- term)² to x² + x

3(x² + 2( )x + - ) = 15

3(x + )² - = 15 ( add to both sides )

3(x + )² = 15 + = ( divide both sides by 3 )

(x + )² = ( take the square root of both sides )

x + = ± = ± ( subtract from both sides )

x = - ± , then

x = - - = - 3

x = - + =

how am i supposed to answer

step-by-step explanation:

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: