I don't think that there is enough info for this problem, but could someone try to help?

12

Step-by-step explanation:

Rectangle : Let length = b & width = a

PQ = QR = 6

LR = QR - PL = 6 - a

ΔPQR ~ ΔMLR

In similar triangles, corresponding sides are in same ratio.

6 - b = a

6 = a + b

a +b = 6

Perimeter of rectangle = 2*(length +width}

       = 2*(a+ b)

       = 2 * 6

       = 12  

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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