What coordinates for point c would make pqt simular to abc

A. (7, -5)

Step-by-step explanation:

The given coordinates of the vertices of ΔPQT are;

P(-2, 5), Q(-2, 1) and T(-5, 1)

The length of the side TQ = 3 units

The length of the side PQ = 4 units

Therefore, the length of the side PT = √(3² + 4²) = 5

The coordinates of the line segment AB = A(1, 3), B(1, -5)

Therefore, using a scale factor of 2, where the sides PQ and AB are corresponding sides, we have;

Where BC is the corresponding side to the TQ on ΔPQT, we have;

The length of BC = 2 × The length of TQ = 2 × 3 units = 6 units (distant from B along the x-axis)

Therefore, the possible points for the point C are;

C(1 - 6, -5) or C(1 + 6, -5)

C(-5, -5) or C(7, -5)

Therefore, the correct option is option A. C(7, -5).

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )