Complete factorization of x^3+4x^2-20x-48

 (x + 6) • (x + 2) • (x - 4)

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

 (((x3) +  22x2) -  20x) -  48

STEP

2

:

Checking for a perfect cube

2.1    x3+4x2-20x-48  is not a perfect cube

Trying to factor by pulling out :

2.2      Factoring:  x3+4x2-20x-48  

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  x3-48  

Group 2:  4x2-20x  

Pull out from each group separately :

Group 1:   (x3-48) • (1)

Group 2:   (x-5) • (4x)

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

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