The planet Mercury travels in an elliptical orbit with eccentricity 0.203. Its minimum distance from the Sun is 4.5 x 10^7 km. If the perihelion distance from a planet to the Sun is a(1 - e) and the aphelion distance is a(1 + e), find the maximum distance (in km) from Mercury to the Sun. Pick from the following:1. 7.7 x 10^7 km.2. 6.6 x 10^7 km.3. 6.8 x 10^7 km.

Option C

Step-by-step explanation:

From the question we are told that:

Eccentricity

Minimum distance from the Sun

Perihelion distance from a planet to the Sun is

Aphelion distance

Generally the equation for Perihelion distance is mathematically given by

Generally the equation for Aperihelion distance is mathematically given by

Option C

answer

a,b, and d

explanation

a reflection angle is more than

but less than;

an angle that measures

is a reflex angle.(true)

an angle that measures less than

is acute.(true)

provided we are considering angles greater or equal to zero.

an acute angle lies in the range.

an obtuse angle is less than 180° but more than 90°

an angle that measures 300° is obtuse (false)

an angle that measures 65° is an acute angle.(true)

the final price would be 29.6925

step-by-step explanation:

39.59 minus 25% equals 29.6925