You decide to move out of your college's dorms and get an apartment, and you want to discuss the budget with your roommate. You know that your monthly grocery bill will depend on a number of factors, such as whether you are too busy to cook, whether you invite guests for meals frequently, how many special holiday meals you will cook, etc. In particular, G will have an approximate normal distribution with a variance of 2500 and a mean: μ=300+10M−100B+50H

Where M is the number of meals to which you invite guests, and E[M]=8. B is a measure for how busy you are and assume it is U[0,1]. H is a variable that takes on the value 1 for holiday months of November, December, and January and 0 otherwise.

a. What is the mean of G in a November, where M=10 and B=0.5?
b. What is E(G)?

a. 400

b. 342.5

Step-by-step explanation:

The mean in this question has been given as

μ=300+10M−100B+50H

where M = 10

B = 0.5

H = 1

we put these into the formula of the mean above

μ=300+10(10)−100(0.5)+50(1)

μ = 300 + 100 - 50 + 50

= 400

So the mean of G in november is = 400

b.  We are to find E[G] here

= E[ 300+10M−100B+50H]

m = 8

B = 0.5 or 1/2

h = 1/4

E[ 300+10x8−100x0.5+50*0.25]

= 300+80-50+12.5

= 342.5

the value for E[G] is therefore 342.5

thank you

idk

step-by-step explanation:

15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

you.