In this problem, x = c1 cos t + c2 sin t is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the second-order IVP consisting of this differential equation and the given initial conditions. x(π/4) = 2 2 , x'(π/4) = 0

Differentiate the given solution:

Now, given that x (π/4) = √2/2 … (I'm assuming there are symbols missing somewhere) … you have

Similarly, given that x' (p/4) = 0, you have

From this result, it follows that

So the particular solution to the DE that satisfies the given conditions is

angle addition postulate

2x=56

step-by-step explanation:

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.