A ball is thrown into the air with an upward velocity of 36 ft/s. It’s height h in feet after t seconds is given by the function h = -16t^2 + 36t + 9. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the balls maximum height ?

Time taken for the ball to hit the ground back = 3.08 s

Step-by-step explanation:

h(t)= -16t² + 48t + 4

when will rhe object come back to hit rhe ground?

When the ball is at the level.of the ground, h(t) = 0.

0 = -16t² + 48t + 4

-16t² + 48t + 4 = 0

Solving the quadratic equation

t = 3.08 s or t = -0.08 s

Since the time cannot be negative,

Time taken for the ball to hit the ground back = 3.08 s

Hope this Helps!!!

Step-by-step explanation:

the answer is 48m^2!

step-by-step explanation:

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3