A restaurant sold 250 drinks in a night. Some of the drinks were sold for $2 each, and the rest for $5 each. If the total sales of drinks for the night was $830, how many $2 drinks were sold? 110
140
145
150
155

?

140

Step-by-step explanation:

Suppose,

x drinks were sold for 2$

y drinks were sold for 5$

therefore, x+y = 250( 1 )

and 2x+5y = 830( 2 )

multiply equation ( 1 ) with 2,

2x+2y = 500( 3 )

Subtract equation ( 3) from (2)

3y = 330

or, y = 110

so, x = 140

so, 140 drinks were sold for 2$