Write the equation for a parabola with a focus at (-3,-5)(−3,−5)left parenthesis, minus, 3, comma, minus, 5, right parenthesis and a directrix at x=-7x=−7x, equals, minus, 7.

(y + 5)² = -16(x + 5)

Step-by-step explanation:

We are told the focus is at (-3, -5)

Directrix is at x = -7

This is a horizontal parabola and thus the general equation is;

(y - k)² = -4p(x - h)

Where;

(h, x) is the coordinate of the vertex.

The axis where the point where the axis of symmetry meets the directrix is at; (-7, -5) since directrix is at x = -7

Thus, coordinates of vertex is;

(-7 + (-3))/2, (-5 + (-5))/2

> (-5, -5)

Thus, equation is;

(y - (-5))² = -4p(x - (-5))

(y + 5)² = -4p(x + 5)

Where p is the distance from vertex to directrix. Thus;

p = -(-7 - (-3))

p = -(-7 + 3)

p = 4

Thus;

(y + 5)² = -4(4)(x + 5)

(y + 5)² = -16(x + 5)

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right