Mathematics, 14.07.2021 21:10 MGA20078
h(t)= ⎩ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎧ 3 t +6 t(t+4) t 2 +t+1 , , , t∈(−∞,−3) t∈[−3,3) t∈[3,∞) h(0)=h(0)=h, left parenthesis, 0, right parenthesis, equals
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h(t)= ⎩ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎧ 3 t +6 t(t+4) t 2 +t+1 , , , t∈(−∞,−3) t∈[−3,3)...
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