Work out the mean for the data set below:
403, 404
Give your answer as a decimal.

605.5

Step-by-step explanation:

When you do a frequency table for this question,the zigma F becomes 2 and the zigma fx becomes 1211.Because you will multiply the marks by the frequency to get the zigma fx so after getting them you add it.Which becomes 403+808=1211.the formula for finding the mean too is zigma fx/zigma f: 1211/2=605.5

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

$75.00

step-by-step explanation:

i = prt

i = 1,5000 * 0.025 * 2

i = 75