The amount of water dispensed by a water dispenser is normally distributed, with a mean of 11.60 ounces and a standard deviation of 0.15 ounces. In
which range will the amount of water dispensed be found 68% of the time?
A. 11.30 ounces to 11.90 ounces
B. 11.15 ounces to 12.05 ounces
C. 11.45 ounces to 11.75 ounces
D. 11.00 ounces to 12.20 ounces
SUBMIT

The correct answer is - C.  11.45 ounces to 11.75 ounces.

Step-by-step explanation:

According to the empirical rule of the distribution for 68% falls under the normal curve falls within 1 standard deviation of the mean.

That is:

μ±δ

From the given information, the mean is

μ = 11.60

and the standard deviation is

δ = 0.15

We substitute the given parameters to obtain;

11.60±0.15

11.75 and 11.45

This means the lower limit is

11.45

and the upper limit is

11.75

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

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step-by-step explanation: