See screenshot below​

A&D

Step-by-step explanation:

we want to solve the following equation for x:

to do so let be u and transform the equation:

By Zero product property we obtain:

Solve the equation for u which yields:

substitute back:

take logarithm of Base 2 in both sides of the both equations:

hence,

( A ) and ( D )

Step-by-step explanation:

( 2^x -3 ) ( ) = 0

- 3 = 0

2^x - 4 = 0

- 3 = 0 ,

x = (3) , x = 2

The equation has two solutions;

= (3) , = 2.

step-by-step explanation:

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