Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials and the probability of obtaining a success. P(X > 3), n = 5, p = 0.2

0.0064

0.00032

Step-by-step explanation:

Given the details:

P(X > 3), n = 5, p = 0.2

The binomial distribution is related using the formula:

P(x = x) = nCx * p^x * q^(n-x)

q = 1 - p = 1 - 0.2 = 0.8

P(X > 3) = p(x = 4) + p(x = 5)

P(x = 4) = 5C4 * 0.2^4 * 0.8^1 = 5 * 0.2^4 * 0.8^1 = 0.0064

P(x = 5) = 5C5 * 0.2^5 * 0.8^0 = 1 * 0.2^5 * 0.8^0 = 0.00032

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

it is c, trust i got your back lol

step-by-step explanation: