What is the domain of the function f(x) = sqr root 1/3x + 2?
x<=-6
x>6
x<6
x>=-6

the answer is 150.6

step-by-step explanation:

you multiply .02 by 30 and get .6.

and then you multiply 5.00 by 30 and get 150.

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i hope this with your

1.) 21

2.) 0.453

3.) 1.5

4.) 48

5.) $ 22

step-by-step explanation: